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  • Open Daily: 10am - 10pm
    Alley-side Pickup: 10am - 7pm

    3038 Hennepin Ave Minneapolis, MN
    612-822-4611

Open Daily: 10am - 10pm | Alley-side Pickup: 10am - 7pm
3038 Hennepin Ave Minneapolis, MN
612-822-4611
An Elementary Treatise on Alternating Currents

An Elementary Treatise on Alternating Currents

Rhodes, William Gould

Paperback

General World History

Currently unavailable to order

ISBN10: 115264677X
ISBN13: 9781152646773
Publisher: General Books
Pages: 138
Weight: 0.47
Height: 0.32 Width: 9.01 Depth: 5.98
Language: English
This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1902 Excerpt: ...+ 2SV 1 = P jis/PE-/V-2rPw + 2SW)2-P$W-e2-2rwf + WJ (14) Now, i must be real, therefore i2 must be real and positive. This gives us as a first condition that the quantity under the square root must be positive, or, in the limit, zero. That is--(PE2-Pe-2rPw + 2S2e2f is greater than or equal to P(E2-e2-2rw)2 + 4#2ti2 Since--P = r2 + S2 this reduces to--Pe2E2 is greater than or equal to rV 4-2Prwe2 4-Pw2 or, taking the square root of both sides--leE is greater than or equal to re2 + Pw.. (15) The limiting values of e, for any given output, w, are therefore given by the equation--re2-IeE + Pw = 0 (16) provided, at the same time, the condition--PE2--Pe2--2rPw+2S2e2 is greater than or equal to zero (17) is satisfied, since this is necessary in order that i2 may be positive. It is not difficult to show that (17) is satisfied by all values of w and e which satisfy (15), for, by (15), we have--Pw is less than or equal to IeE--re2 therefore--PE2-Pe2-2rPw + 2S2e2 is greater than PE2-Pe2-2r(IeE-re2) + 2W greater than PE2-2rIeE+ r2e2-S2e2 greater than (IE-re)2+S2e2 Thus, when (15) is satisfied, so also is (17). It will, therefore, be sufficient to see that condition (15) is always satisfied. Provided, then, that--re2--IEe + Pw is equal to or less than zero the current will be real, and we shall have a possible working condition of the plant. Solving equation (10) we get--IE /PE-iPrw es=Yr --Tr = E s/W-4rw (18) This gives the maximum and minimum values of e when E and w are given. If we consider to as variable, it also gives the greatest possible value of e for a given value of the generator E.M.F.; this occurs when w = 0, and the greatest possible value of e is given by--We have noticed before ( 87) that the generator E.M.F. is not necessarily g...

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